Question

\(\left\{{}\begin{matrix}a-b=2\\ab-a+b=34\end{matrix}\right.\)

\(\left\{{}\begin{matrix}6\left(x+y\right)=10x+y\\xy+25=10y+x\end{matrix}\right.\)

Em đang cần gấp ạ

Answer 1

1) \(\Leftrightarrow\left\{{}\begin{matrix}a=2+b\\b\left(2+b\right)-\left(2+b\right)-34=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}a=2+b\\b^2+b-36=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}a=2+b\\b=\frac{-1\pm\sqrt{145}}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=2+\frac{-1\pm\sqrt{145}}{2}\\b=\frac{-1\pm\sqrt{145}}{2}\end{matrix}\right.\)