Question

\(\left\{{}\begin{matrix}3xy+x=6y+2\\\frac{5}{2x+1}+\frac{4y}{3y+1}=3\end{matrix}\right.\)

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}x\left(3y+1\right)=6y+2\\\frac{5}{2x+1}+\frac{4y}{3y+1}=3\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\1+\frac{4y}{3y+1}=3\end{matrix}\right.\) Đk : \(\left\{{}\begin{matrix}x\ne-\frac{1}{2}\\y\ne-\frac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\4y=2\left(3y+1\right)\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-1\end{matrix}\right.\) ( TM )