b) \(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
\(\Rightarrow\left(x-\dfrac{2}{9}\right)^3=\left[\left(\dfrac{2}{3}\right)^2\right]^3=\left(\dfrac{4}{9}\right)^3\)
\(\Rightarrow x-\dfrac{2}{9}=\dfrac{4}{9}\)
\(\Rightarrow x=\dfrac{2}{3}\)
Thui làm hộ cho:
\(\left(8x-1\right)^{2n-1}:5=5^{2n}\)
\(\left(8x-1\right)^{2n-1}=5^{2n}.5\)
mà àm cho khỏi nhân 5 hay chia 5 vậy