\(\left|2x-3\right|-\left|3x+2\right|=0\)
\(\Rightarrow\left|2x-3\right|=\left|3x+2\right|\)
\(\Rightarrow2x-3=\pm\left(3x+2\right)\)
+) \(2x-3=3x+2\)
\(\Rightarrow-x=5\)
\(\Rightarrow x=-5\)
+) \(2x-3=-\left(3x+2\right)\)
\(\Rightarrow2x-3=-3x-2\)
\(\Rightarrow5x=1\)
\(\Rightarrow x=\frac{1}{5}\)
Vậy \(x\in\left\{-5;\frac{1}{5}\right\}\)