\(\Leftrightarrow\left|2-3x^2\right|\ge\left|6-x^2\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}2-3x^2\ge6-x^2\\2-3x^2\le x^2-6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2\ge-2\left(ld\right)\\x^2\ge2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x\ge\sqrt{2}\\x\le-\sqrt{2}\end{matrix}\right.\)