Gọi biểu thức trên là A. Ta có
\(A=\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right)....\left(1-\dfrac{1}{2017}\right)\)
\(A=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}....\dfrac{2016}{2017}=\dfrac{1.2.3...2016}{2.3.4..2017}=\dfrac{1}{2017}\)