a) CTHH: Mg(SO4)------> PTK: 24 + 32 + 64 = 120 DvC
a/ ta có CTHH: \(Mg^{II}_x\left(SO_4\right)^{II}_y\)
\(\rightarrow II.x=II.y\rightarrow\dfrac{x}{y}=\dfrac{II}{II}=\dfrac{1}{1}\rightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)
\(\rightarrow CTHH:MgSO_4\)
\(PTK=24+32+4.16=120\left(đvC\right)\)
b/ ta có CTHH: \(Ca^{II}_x\left(PO_4\right)^{III}_y\)
\(\rightarrow II.x=III.y\rightarrow\dfrac{x}{y}=\dfrac{III}{II}=\dfrac{3}{2}\rightarrow\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\)
\(\rightarrow CTHH:Ca_3\left(PO_4\right)_2\)
\(PTK=3.40+\left(31+4.16\right).2=310\left(đvC\right)\)
các ý còn lại làm tương tự