Question

i) 25*(3x-1/2)^2=16

k) 3*(3x-1/2)^3+1/9=0

l) 1/2x+2/3x-1=-3 và 1/3

m) x+1/3=-3/-9

Answer 1

i)\(=>\left(3x-\dfrac{1}{2}\right)^2=\dfrac{25}{16}=>\left[{}\begin{matrix}3x-\dfrac{1}{2}=\dfrac{5}{4}\\3x-\dfrac{1}{2}=-\dfrac{5}{4}\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}3x=\dfrac{7}{4}\\3x=-\dfrac{3}{4}\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

k)\(=>\left(3x-\dfrac{1}{2}\right)^3=-\dfrac{1}{27}\)

\(=>3x-\dfrac{1}{2}=-\dfrac{1}{3}\)

\(=>3x=\dfrac{1}{6}=>x=\dfrac{1}{6}:3=\dfrac{1}{18}\)

Answer 2

m)\(=>x+\dfrac{1}{3}=\dfrac{1}{3}=>x=\dfrac{1}{3}-\dfrac{1}{3}=0\)

l) 1/2x+2/3x-1=-3 và 1/3(tui ko hiểu)