Phân thức đại số

Đức Tài

https://loigiaihay.com/bai-25-trang-47-sgk-toan-8-tap-1-c43a25368.html#ixzz5YLV0H7he

giải dùm bài ( e ) thôi thankyou ~^_^~ (giải ngắn thôi)
Huỳnh lê thảo vy
30 tháng 11 2018 lúc 20:55

a) 52x2y+35xy2+xy352x2y+35xy2+xy3

=5.5y22x2y.5y2+3.2xy5xy2.2xy+x.10x2y3.10x2=5.5y22x2y.5y2+3.2xy5xy2.2xy+x.10x2y3.10x2

=25y210x2y3+6xy10x2y3+10x310x2y3=25y210x2y3+6xy10x2y3+10x310x2y3

=25y2+6xy+10x310x2y3=25y2+6xy+10x310x2y3

b) x+12x+6+2x+3x(x+3)=x+12(x+3)+2x+3x(x+3)x+12x+6+2x+3x(x+3)=x+12(x+3)+2x+3x(x+3)

=x(x+1)2x(x+3)+2(2x+3)2x(x+3)=x2+x+4x+62x(x+3)=x(x+1)2x(x+3)+2(2x+3)2x(x+3)=x2+x+4x+62x(x+3)

=x2+5x+62x(x+3)=x2+2x+3x+62x(x+3)=x2+5x+62x(x+3)=x2+2x+3x+62x(x+3)

=x(x+2)+3(x+2)2x(x+3)=x(x+2)+3(x+2)2x(x+3)=(x+2)(x+3)2x(x+3)=x+22x=(x+2)(x+3)2x(x+3)=x+22x

c) 3x+5x2−5x+25−x25−5x=3x+5x2−5x+x−255x−253x+5x2−5x+25−x25−5x=3x+5x2−5x+x−255x−25

=3x+5x(x−5)+x−255(x−5)=5(3x+5)5x(x−5)+x(x−25)5x(x−5)=3x+5x(x−5)+x−255(x−5)=5(3x+5)5x(x−5)+x(x−25)5x(x−5)

=15x+25+x2−25x5x(x−5)=x2−10x+255x(x−5)=15x+25+x2−25x5x(x−5)=x2−10x+255x(x−5)

=(x−5)25x(x−5)=x−55x=(x−5)25x(x−5)=x−55x

d) x2+x4+11−x2+1=1+x2+x4+11−x2x2+x4+11−x2+1=1+x2+x4+11−x2

=(1+x2)(1−x2)1−x2+x4+11−x2=(1+x2)(1−x2)1−x2+x4+11−x2

=1−x4+x4+11−x2=21−x2=1−x4+x4+11−x2=21−x2

e) 4x2−3x+17x3−1+2x−1x2+x+1+61−x4x2−3x+17x3−1+2x−1x2+x+1+61−x

4x2−3x+17(x−1)(x2+x+1)+2x−1x2+x+1+−6x−14x2−3x+17(x−1)(x2+x+1)+2x−1x2+x+1+−6x−1

=4x2−3x+17(x−1)(x2+x+1)+(2x−1)(x−1)(x−1)(x2+x+1)=4x2−3x+17(x−1)(x2+x+1)+(2x−1)(x−1)(x−1)(x2+x+1)+−6(x2+x+1)(x−1)(x2+x+1)+−6(x2+x+1)(x−1)(x2+x+1)

=4x2−3x+17+(2x−1)(x−1)−6(x2+x+1)(x−1)(x2+x+1)=4x2−3x+17+(2x−1)(x−1)−6(x2+x+1)(x−1)(x2+x+1)

=4x2−3x+17+2x2−3x+1−6x2−6x−6(x−1)(x2+x+1)=4x2−3x+17+2x2−3x+1−6x2−6x−6(x−1)(x2+x+1)

=−12x+12(x−1)(x2+x+1)=−12(x−1)(x−1)(x2+x+1)=−12x+12(x−1)(x2+x+1)=−12(x−1)(x−1)(x2+x+1)

=−12x2+x+1=−12x2+x+1




Các câu hỏi tương tự
Minh Thư Nguyễn Ngọc
Xem chi tiết
Nguyễn đức mạnh
Xem chi tiết
Phạm Nguyễn Đăng khải
Xem chi tiết
Bùi Phúc An
Xem chi tiết
Yoidsxc Wed
Xem chi tiết
Trọng Nghĩa Nguyễn
Xem chi tiết
Nobody
Xem chi tiết
DuyAnh Phan
Xem chi tiết
Trần Khánh Linh
Xem chi tiết