Gọi \(\left\{{}\begin{matrix}n_{C3H7OH}:x\left(mol\right)\\_{C6H5OH}:y\left(mol\right)\end{matrix}\right.\)
Ta có:
\(n_{H2}=\frac{3,36}{22,4}=0,15\left(mol\right)\)
PTHH:
\(2C_3H_7OH+2Na\rightarrow2C_3H_7ONa+H_2\)
\(2C_6H_5OH+2Na\rightarrow2C_6H_5ONa+H_2\)
Giải hệ PT:
\(\left\{{}\begin{matrix}60x+94y=21,4\\x+y=0,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,2\\y=0,1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{C3H7OH}=\frac{0,2.60}{21,4}.100\%=56,07\%\\\%m_{C6H5OH}=100\%-56,07\%=43,93\%\end{matrix}\right.\)
\(C_6H_5OH+NaOH\rightarrow C_6H_5ONa+H_2O\)
\(\Rightarrow n_{NaOH}=n_{C6H5OH}=0,1\left(mol\right)\)
\(\Rightarrow V_{NaOH}=\frac{0,1}{0,2}=0,5\left(l\right)\)
