Question

Hoàn thành sơ đồ phản ứng:

tinh bột => Glucozơ => rượu etylic => Axitaxetic => Ety axetat

Answer 1

(−C6H10O5−)n+nH2O−H2SO4,to−>nC6H12O6

C6H12O6−30−35oC,xtenzim−>2C2H5OH+2CO2

C2H5OH+O2−Men Giấm−>CH3COOH+H2O

CH3COOH+C2H5OH<−H2SO4đ,140oC−>CH3COOC2H5+H2O

Answer 2

\(\left(-C_6H_{10}O_5-\right)n+nH_2O\rightarrow\left(t^o,xt\right)nC_6H_{12}O_6\)

\(C_6H_{12}O_6\rightarrow\left(men.rượu\right)2C_2H_5OH+2CO_2\)

\(C_2H_5OH+O_2\rightarrow\left(men.giấm\right)CH_3COOH+H_2O\)

\(CH_3COOH+C_2H_5OH\rightarrow\left(t^o,H_2SO_4\left(đ\right)\right)CH_3COOC_2H_5+H_2O\)

Answer 3

(-C6H10O5-)_n + nH2O => ( H2SO4đ,t^o ) nC6H12O6

C6H12O6 => ( men rượu,t^o ) 2CO2 + C2H5OH

C2H5OH + O2 => ( men giấm ) CH3COOH + H2O

CH3COOH + C2H5OH => ( H2SO4đ,t^o ) < hai chiều > CH3COOC2H5 + H2O

Answer 4

(−C6H10O5−)n+nH2O−H2SO4,to−>nC6H12O6

C6H12O6−30−35oC,xtenzim−>2C2H5OH+2CO2

C2H5OH+O2−Men Giấm−>CH3COOH+H2O

CH3COOH+C2H5OH<−H2SO4đ,140oC−>CH3COOC2H5+H2O