Fe+2HCl-->FeCl2+H2
nH2=2,24\22,4=0,1 mol
=>mFe=0,1.56=5,6g
=>mAl2O3=5,1 g
Al2O3+6HCl-->2AlCl3+3H2O
nAl2O3=5,1\102=0,05 mol
=>mAlCl3=0,1.133,5=13,35g
=>mFeCl2=0,1.127=12,7g
=>m=13,35+12,7=26,05 g
=>mHCl=(0,2+0,3).36,5=18,25g
c)=>mddHCl=146 g