PTHH: \(M+2HCl\rightarrow MCl_2+H_2\)
\(N+2HCl\rightarrow NCl_2+H_2\)
Ta có: \(m_{tăng}=39,6-11,2=28,4\left(g\right)=m_{Cl}\)
\(\Rightarrow n_{Cl}=\frac{28,4}{35,5}=0,8\left(mol\right)=n_{HCl}\) \(\Rightarrow n_{H_2}=0,4\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,4\cdot22,4=8,96\left(l\right)\)