Cu k phản ứng với HCl
\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(n_{H_2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(m_{Cu}=\sum m-m_{Zn}=19,4-\left(0,2.65\right)=6,4\left(g\right)\)
\(PTHH:Cu+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2Ag\)
\(n_{Cu}=\frac{6,4}{64}=0,1\left(mol\right)\)
\(V_{AgNO_3}=\frac{n}{C_M}=\frac{0,1.2}{1}=0,2\left(l\right)=200\left(ml\right)\)
Zn + 2HCl = ZnCl2 + H2
0,2...............................0,2
nH2=4,48:22,4=0,2 mol
=> nZn=nH2 =0,2 mol
=> mZn=0,2.65=13 g
=> mCu=mX=19,4-13=6,4 g
Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
0,1.......0,2
nCu=6,4:64=0,1 mol
=> nAgNO3=2.0,1=0,2 mol
=> V =0,2:1=0,2 l