Châu Anh
\(PTHH:\)
\(CaO+2CH_3COOH--->(CH_3COO)_2Ca+H_2O\)
\(CaCO_3+2CH_3COOH--->(CH_3COO)_2Ca+CO_2+H_2O\)
\(a)\)
\(nCO_2=0,1(mol)\)
\(=>nCaCO_3=0,1(mol)\)
\(=>mCaCO_3=10(g)\)
\(\%mCaCO_3=\dfrac{10.100}{15,5}=64,52\%\)
\(=>\%mCaO=100\%-64,52\%=35,48\%\)
\(b)\)
\(mCaO=15,5-10=5,5(g)\)
\(=>nCaO=\dfrac{11}{112}\left(mol\right)\)
Theo PTHH (1) và (2) \(\sum nCH_3COOH=0,2+\dfrac{11}{56}=\dfrac{111}{280}\left(mol\right)\)
\(\Rightarrow mCH_3COOH=\dfrac{333}{14}\left(g\right)\)
\(C\%CH_3COOH=\dfrac{\dfrac{333}{14}}{200}.100=11.89\%\)
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