Na2O+H2O--> 2NaOH
nNa2o= m/M = 12,4/62=0,2mol
==> nNaOH= 2 x 0,2 = 0,4mol
==> mNaOH= M x n= 0,4 x 40=16 gram
PTPƯ: Na2O + H2O ---> 2NAOH
nNa2O= \(\dfrac{m}{M}=\) \(\dfrac{12,4}{55}\)\(\approx\)0,2 (mol)
nNaOH = 2 nNa20= 2\(\times\)0,2= 0,4 (mol)
mNaOH= n\(\times\)M= 0,4\(\times\)40= 16 (g)