Gọi \(n_{Mg}=x\rightarrow m_{Mg}=24x\)
\(n_{Al}=y\rightarrow m_{Al}=27y\)
\(n_{Zn}=z\rightarrow m_{Zn}=65z\)
\(24x+27y+65z=19,46\left(g\right)\left(1\right)\)
Do \(m_{Mg}=m_{Al}\)
---> 24x=27y------>24x-27y=0(2)
n H2=16,352/224=0,73(mol)
Mg+2HCl---.>MgCl2+H2
x-------------------------------x
2Al+6HCl--->2AlCl3+3H2
y-------------------------1,5y
Zn+2HCl--->.ZnCl2+H2
z-----------------------------z
-->x+1,5y+z=0,73(3)
Từ 1,2 ,3 ta có hpt
\(\left\{{}\begin{matrix}24x+27y+65z=19,46\\24x-27y=0\\x+1,5y+z=0,73\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,27\\y=0,24\\z=0,1\end{matrix}\right.\)
m Al=m Mg=0,27.24=6,48(g)
m Zn=19,46-6,48.2=6,5(g)
b)
Theo pthh
Tổng n HCl=2n H2=1,46(mol)
V HCl=1,46/2=0,73(l)
Do lấy dư 10% nên V HCl=0,73./10%=7,3
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