\(n_{CO_2}=\dfrac{17.6}{44}=0.4\left(mol\right)\)
\(n_{H_2O}=\dfrac{10.8}{18}=0.6\left(mol\right)\)
\(m_O=m_A-m_C-m_H=6-0.4\cdot12-0.6\cdot2=0\)
\(\text{A chứa : C và H}\)
\(CT:C_xH_y\)
\(x:y=0.4:1.2=1:3\)
\(CTnguyên:\left(CH_3\right)_n\)
\(M_A=15\cdot2=30\left(g\text{/}mol\right)\)
\(\Leftrightarrow15n=30\)
\(\Leftrightarrow n=2\)
\(CT:C_2H_6\)
\(\)