Question

help !!!

Answer 1

Ta có:\(\frac{1+3y}{12}=\frac{1+6y}{16}\Rightarrow16\left(1+3y\right)=12\left(1+6y\right)\)

\(\Rightarrow16+48y=12+72y\)

\(\Rightarrow16-12=72y-48y\)

\(\Rightarrow24y=4\)

\(\Rightarrow y=\frac{1}{6}\)

\(\Rightarrow\frac{1+6\cdot\frac{1}{6}}{16}=\frac{1+9\cdot\frac{1}{6}}{4x}\)

\(\Rightarrow\frac{1}{8}=\frac{2,5}{4x}\)

\(\Rightarrow\frac{5}{8}x=\frac{1}{8}\)

\(\Rightarrow x=\frac{1}{8}:\frac{5}{8}\)

\(\Rightarrow x=\frac{1}{5}\)

Answer 2

Cho sửa lại:\(\frac{1}{8}=\frac{2,5}{4x}\)

\(\Rightarrow\frac{5}{8x}=\frac{1}{8}\)

\(\Rightarrow\frac{5}{8}\cdot\frac{1}{x}=\frac{1}{8}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{8}:\frac{5}{8}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{5}\)

\(\Rightarrow x=5\)