Question

Help Me😭😭😭

Answer 1

a: \(\left(\dfrac{4}{5}\right)^{2x+7}=\dfrac{625}{256}\)

=>2x+7=-4

hay x=-11/2

b: \(\left(4x-5\right)^4=\left(4x-5\right)^2\)

\(\Leftrightarrow\left(4x-5\right)^2\cdot\left(4x-4\right)\left(4x-6\right)=0\)

hay \(x\in\left\{\dfrac{5}{4};1;\dfrac{3}{2}\right\}\)

d: \(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

=>8x-1=5

hay x=3/4