\(9x^2-24x+16\)
\(=\left(3x-4\right)\left(3x-4\right)\)
\(9x^2-24x+16\\ =\left[\left(3x\right)^2-2.3x.4+4^2\right]=\left(3x-4\right)^2\)
\(9x^2-24x+16=\left(3x\right)^2-2.3.4+4^2=\left(3x-4\right)^2\)
\(9x^2-24x+16=9x^2-12x-12x+16\)
\(=\left(9x^2-12x\right)-\left(12x-16\right)=3x.\left(3x-4\right)-3.\left(3x-4\right)\)
\(=\left(3x-4\right).\left(3x-3\right)\)
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Nhầm mình làm lại!
\(9x^2-24x+16=9x^2-12x-12x+16\)
\(=\left(9x^2-12x\right)-\left(12x-16\right)=3x.\left(3x-4\right)-4.\left(3x-4\right)\)
\(=\left(3x-4\right).\left(3x-4\right)=\left(3x-4\right)^2\)
\(9x^2-24x+16\)
\(=3^2x^2-24x+4^2\)
\(=\left(3x\right)^2-24x+4^2\)
\(=\left(3x-4\right)^2\)
\(9x^2-24x+16=\left(3x\right)^2-2\times3\times4x+4^2=\left(3x-4\right)^2\)
\(9x^2-24x+16=\left(3x\right)^2-2.3x.4+4^2=\left(3x-4\right)^2\)