\(n_{H_2}=\dfrac{22,4}{22,4}=1\left(mol\right)=>m_{H_2}=1.2=2\left(g\right)\)
\(n_{N_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)=>m_{H_2}=0,15.28=4,2\left(g\right)\)
\(n_{CO}=\dfrac{0,896}{22,4}=0,04\left(mol\right)=>m_{CO}=0,04.28=1,12\left(g\right)\)
a: \(n_{H_2}=\dfrac{V}{22.4}=1\left(mol\right)\)
b: \(n_{N_2}=\dfrac{3.36}{22.4}=0.15\left(mol\right)\)