Question

h.-(\(\dfrac{1}{2}\))\(^2\).13\(\dfrac{9}{11}\)-25%.6\(\dfrac{2}{11}\) (. là nhân nhe)

i.57%+1\(\dfrac{2}{15}\):\(\dfrac{68}{25}\)-2,82

Answer 1

Giải:

h) \(\left(-\dfrac{1}{2}\right)^2.13\dfrac{9}{11}-25\%.6\dfrac{2}{11}\)

\(=\dfrac{1}{4}.\dfrac{152}{11}-\dfrac{1}{4}.\dfrac{68}{11}\)

\(=\dfrac{1}{4}\left(\dfrac{152}{11}-\dfrac{68}{11}\right)\)

\(=\dfrac{1}{4}.\dfrac{84}{11}=\dfrac{21}{11}\)

Vậy ...

i) \(57\%+1\dfrac{2}{15}:\dfrac{68}{25}-2,82\)

\(=\dfrac{57}{100}+\dfrac{17}{15}:\dfrac{68}{25}-\dfrac{141}{50}\)

\(=\dfrac{57}{100}+\dfrac{2}{15}-\dfrac{141}{50}\)

\(=\dfrac{-127}{60}\)

Vậy ...

Answer 2

h. \(\left(-\dfrac{1}{2}\right)^2\times13\dfrac{9}{11}-25\%\times6\dfrac{2}{11}\)

= \(\dfrac{1}{4}\times\dfrac{150}{11}-\dfrac{1}{4}\times34\)

= \(\dfrac{75}{22}-\dfrac{17}{2}\)

= \(\dfrac{75}{22}-\dfrac{187}{22}\)

= \(-\dfrac{56}{11}\)

i. \(57\%+1\dfrac{2}{15}\div\dfrac{68}{25}-2,82\)

= \(\dfrac{57}{100}+\dfrac{17}{15}\div\dfrac{68}{25}-\dfrac{282}{100}\)

= \(\dfrac{57}{100}+\dfrac{17}{15}\times\dfrac{25}{68}-\dfrac{282}{100}\)

= \(\dfrac{57}{100}+\dfrac{5}{3}-\dfrac{282}{100}\)

=\(\dfrac{5}{3}-\left(\dfrac{57}{100}-\dfrac{282}{100}\right)\)

= \(\dfrac{5}{3}-\left(-\dfrac{215}{100}\right)\)

= \(\dfrac{5}{3}-\left(-\dfrac{43}{20}\right)\)

= \(\dfrac{5}{3}+\dfrac{43}{30}\)

= \(\dfrac{50}{30}+\dfrac{43}{30}\)

= \(\dfrac{31}{10}\)

Answer 3

h) Ta có:\(-\left(\dfrac{1}{2}\right)^2\).13\(\dfrac{9}{11}\) - 25%.6\(\dfrac{2}{11}\)

= \(-\dfrac{2}{2}\).\(\dfrac{152}{11}\) - \(\dfrac{25}{100}\).\(\dfrac{68}{11}\)

= -1 .\(\dfrac{152}{11}\) - \(\dfrac{1}{4}\) . \(\dfrac{68}{11}\)

= \(\dfrac{-152}{11}\) - 1.\(\dfrac{17}{11}\)

= \(\dfrac{-152-17}{11}\)

= \(\dfrac{-152+\left(-17\right)}{11}\)

= \(\dfrac{-169}{11}\)

i) Ta có: 57% + 1\(\dfrac{2}{15}\): \(\dfrac{68}{25}\) - 2,82

= \(\dfrac{57}{100}\) + \(\dfrac{17}{15}:\dfrac{68}{25}\) - \(\dfrac{282}{100}\)

= \(\dfrac{17}{15}.\dfrac{68}{25}\)+ \(\dfrac{57}{100}\)-\(\dfrac{282}{100}\)

= \(\dfrac{1156}{375}\) + \(\dfrac{57+\left(-282\right)}{100}\)

= \(\dfrac{1156}{375}\) + \(\dfrac{-225}{100}\)

= \(\dfrac{1156}{375}\) + \(\dfrac{-9}{4}\)

= \(\dfrac{4624}{1500}\) + \(\dfrac{-3375}{1500}\)

= \(\dfrac{1249}{1500}\)

Mk nghĩ là như z đó.

Chúc bn học tốt!!!

Answer 4

h, = -(\(\dfrac{1}{2}\))^2 . 13\(\dfrac{9}{11}\)- 25% . 6\(\dfrac{2}{11}\)

= -\(\dfrac{1}{4}\) . \(\dfrac{152}{11}\) - \(\dfrac{25}{100}\) . \(\dfrac{68}{11}\)

= \(\dfrac{1}{4}\) . -\(\dfrac{152}{11}\) - \(\dfrac{1}{4}\) . \(\dfrac{68}{11}\)

= \(\dfrac{1}{4}\) . ( -\(\dfrac{152}{11}\) - \(\dfrac{68}{11}\) )

= \(\dfrac{1}{4}\) . -20

= -5

i, 57% + 1\(\dfrac{2}{15}\) : \(\dfrac{68}{25}\) - 2,82

= \(\dfrac{57}{100}\) + \(\dfrac{17}{15}\) . \(\dfrac{25}{68}\) - \(\dfrac{282}{100}\)

= \(\dfrac{57}{100}\) + \(\dfrac{5}{12}\) - \(\dfrac{282}{100}\)

= \(\dfrac{57}{100}\) - \(\dfrac{282}{100}\) + \(\dfrac{5}{12}\)

= -\(\dfrac{9}{4}\) + \(\dfrac{5}{12}\)

= -\(\dfrac{27}{12}\) + \(\dfrac{5}{12}\)

= -\(\dfrac{22}{12}\) = -\(\dfrac{11}{6}\)