\(a,=\dfrac{x^3-\left(x-1\right)\left(x^2+x+1\right)}{1-x}=\dfrac{x^3-x^3+1}{1-x}=\dfrac{1}{1-x}\\ b,=\dfrac{2x+x^2+3x+2+2-x}{\left(x+2\right)^2}=\dfrac{\left(x+2\right)^2}{\left(x+2\right)^2}=1\)
\(a,=\dfrac{x^3-\left(x-1\right)\left(x^2+x+1\right)}{1-x}=\dfrac{x^3-x^3+1}{1-x}=\dfrac{1}{1-x}\\ b,=\dfrac{2x+x^2+3x+2+2-x}{\left(x+2\right)^2}=\dfrac{\left(x+2\right)^2}{\left(x+2\right)^2}=1\)
\(\dfrac{y}{2x^2-xy}+\dfrac{4x}{y^2-2xy}\)
\(\dfrac{1}{x+2}+\dfrac{3}{x^2-4}+\dfrac{x-14}{\left(x^2+4x+4\right).\left(x-2\right)}\)
\(\dfrac{1}{x+2}+\dfrac{1}{\left(x+2\right).\left(4x+7\right)}\)
\(\dfrac{1}{x+3}+\dfrac{1}{\left(x+3\right).\left(x+2\right)}+\dfrac{1}{\left(x+2\right).\left(4x+7\right)}\)
Giúp mình câu này với mik đang cần gấp
\(\dfrac{2x^2-x}{x-1}\)+\(\dfrac{x+1}{1-x}\)+\(\dfrac{2-x^2}{x-1}\)
Bài 1:tính
a)\(\dfrac{x^2-2^{ }}{x\left(x-1\right)^2}+\dfrac{2-x}{x\left(1-x\right)^2}\)
b)\(\dfrac{3}{2x}+\dfrac{3x-3}{2x-1}+\dfrac{2x^2+1}{4x^2-2x}\)
c)\(\dfrac{x}{x-1}+\dfrac{2}{x^2+x+1}+\dfrac{4x^2-1}{1-x^3}\)
Làm các phép tính sau :
a) \(\dfrac{y}{2x^2-xy}+\dfrac{4x}{y^2-2xy}\)
b) \(\dfrac{1}{x+2}+\dfrac{3}{x^2-4}+\dfrac{x-14}{\left(x^2+4x+4\right)\left(x-2\right)}\)
c) \(\dfrac{1}{x+2}+\dfrac{1}{\left(x+2\right)\left(4x+7\right)}\)
d) \(\dfrac{1}{x+3}+\dfrac{1}{\left(x+3\right)\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(4x+7\right)}\)
Giúp mình câu này với ạ
\(\dfrac{1}{x}\)+\(\dfrac{1}{x+2}\)+\(\dfrac{x-2}{x^2+2x}\)
Cảm ơn!
\(\dfrac{1}{x+3}+\dfrac{8-x}{4x^2+8x}\)
\(\dfrac{3-2x}{\left(x-5\right)\left(x+2\right)}+\dfrac{1}{x+5}\)
1. \(\dfrac{x-1}{x+1}+\dfrac{-\left(x+1\right)}{x-1}+\dfrac{4}{x^2-1}\)
2. \(\dfrac{4-2x+x^2}{2+x}+\left(-2-x\right)\)
3. \(\dfrac{x^3+4x^2+x-6}{x^3+2x^2-x-2}\)
4. \(\dfrac{ab+cx+ax+bx}{ay+2cx+2ax+cy}\)
\(\dfrac{3-x}{\left(x-1\right)\left(x-2\right)}+\dfrac{1+x}{\left(1-x\right)\left(x-2\right)}\) Giúp mình cái, mọi người!
Thực hiện phép tính
a) \(\dfrac{x}{xy-y^2}+\dfrac{2x-y}{xy-x^2}\)
b) \(\dfrac{x^2+2}{x^3-1}+\dfrac{x}{x^2+x+1}+\dfrac{1}{1-x}\)
c) \(\left(x-1\right)-\dfrac{x^2-4}{x+1}\)
d) \(\dfrac{x}{x^2-2x}-\dfrac{x^2+4x}{x^3-4x}-\dfrac{2}{x^2+2x}\)