1,
|x|=2x-1
x=\(\pm\)(2x-1)
1. x=2x-1 2. x=-(2x-1)
=> 1=x =>x=-2x+1
=> 3x=1
=> x=1/3
2, xy=x:y
=> y.y=x:x
y2=1
=> y=\(\pm\)1
1. y=1 2. y=-1
=> x-1=x.1 => x-(-1)=x(-1)
x-1=x( vô lý) x+1=-x
2x=-1
=> x=-1/2
Vậy x=-1/2; y=-1
1,
|x|=2x-1
x=\(\pm\)(2x-1)
1. x=2x-1 2. x=-(2x-1)
=> 1=x =>x=-2x+1
=> 3x=1
=> x=1/3
2, xy=x:y
=> y.y=x:x
y2=1
=> y=\(\pm\)1
1. y=1 2. y=-1
=> x-1=x.1 => x-(-1)=x(-1)
x-1=x( vô lý) x+1=-x
2x=-1
=> x=-1/2
Vậy x=-1/2; y=-1