Question

giúp mình với ạ câu nào cũng được ạ

 

Answer 1

6:

a: \(\Leftrightarrow\dfrac{\sqrt{4}-\sqrt{1}}{4-1}+\dfrac{\sqrt{7}-\sqrt{4}}{7-4}+...+\dfrac{\sqrt{3n+4}-\sqrt{3n+1}}{3}=8\)

=>\(-\sqrt{1}+\sqrt{4}-\sqrt{4}+\sqrt{7}-...-\sqrt{3n+1}+\sqrt{3n+4}=24\)

=>\(\sqrt{3n+4}=24+1=25\)

=>3n+4=625

=>3n=621

=>n=207

b: \(\dfrac{1}{2\sqrt{1}+1\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+...+\dfrac{1}{\left(n+1\right)\sqrt{n}+n\cdot\sqrt{n+1}}=\dfrac{4}{5}\)

=>\(\dfrac{1}{\sqrt{1}}-\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{2}}-\dfrac{1}{\sqrt{3}}+...+\dfrac{1}{\sqrt{n}}-\dfrac{1}{\sqrt{n+1}}=\dfrac{4}{5}\)

=>\(1-\dfrac{1}{\sqrt{n+1}}=\dfrac{4}{5}\)

=>n+1=25

=>n=24