Question

giúp mình với

1, tính

a, \(\dfrac{7}{3}+[\left(\dfrac{-5}{6}\right)+\left(\dfrac{-2}{3}\right)]\)

b, \(\left(3\dfrac{1}{4}-1\dfrac{1}{3}\right)\div\sqrt{\dfrac{16}{25}}\)

Answer 1

\(a,\dfrac{7}{3}+\left[\left(\dfrac{-5}{6}\right)+\left(\dfrac{-2}{3}\right)\right]\)

\(=\dfrac{7}{3}+\left[\dfrac{\left(-5\right)+\left(-4\right)}{6}\right]\)

\(=\dfrac{14}{6}+\dfrac{-9}{6}=\dfrac{5}{6}\)

Answer 2

\(b,\left(3\dfrac{1}{4}-1\dfrac{1}{3}\right):\sqrt{\dfrac{16}{25}}\)

\(=\left(\dfrac{13}{4}-\dfrac{4}{3}\right):\dfrac{4}{5}\)

\(=\left(\dfrac{39-16}{12}\right).\dfrac{5}{4}\)

\(=\dfrac{23}{12}.\dfrac{5}{4}=\dfrac{115}{48}\)