Question

Giúp mình nhé

Answer 1

a) \(\left|x-5\right|-x=3\Leftrightarrow x-5=3+x\)

+)TH1: x>=5 thì pt trở thành:

x-5=3+x <=> 0x=8 (vô nghiệm)

+)TH2: x<5 thì pt trở thành

5-x=3+x <=> 2x=2 <=> x=2(tm)

Vậy x=1

b) \(\left|x\right|+\frac{-1}{4}=\frac{-3}{12}\)

\(\Leftrightarrow\left|x\right|=0\Leftrightarrow x=0\)

c) \(-\left|x\right|+\frac{2}{3}=0\)

\(\Leftrightarrow\left|x\right|=\frac{2}{3}\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{2}{3}\\x=-\frac{2}{3}\end{array}\right.\)

d) \(\left|x-3\right|=3\)

+)TH1: x>=3 thì pt trở thành

x-3=3 <=>x=6(tm)

+)TH2: x<3 thì pt trở thành

x-3=-3 <=> x=0 (tm)

Vậy x={0;6}

Answer 2

a)|x-5|-x=3

TH1:x-5-x=3

       -5=3(vô lý)(loại)

TH2:-(x-5)-x=3

        -x+5-x=3

        2x=2

        x=1

    Vậy x=1

b)\(\left|x\right|+-\frac{1}{4}=-\frac{3}{12}\)

   \(\left|x\right|=0\)

    x=0

Vậy x=0

Answer 3

c)\(-\left|x\right|+\frac{2}{3}=0\)

    \(-\left|x\right|=-\frac{2}{3}\)

TH1:-x=\(-\frac{2}{3}\)

       x=\(\frac{2}{3}\)

TH2:-(-x)=\(-\frac{2}{3}\)

        x=\(-\frac{2}{3}\)

     Vậy x=\(-\frac{2}{3}\);\(\frac{2}{3}\)

d)|x-3|=3

\(\Rightarrow\left[\begin{array}{nghiempt}x-3=3\\x-3=-3\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=6\\x=0\end{array}\right.\)

        Vậy x=6;-3