=>4 căn x-2-2 căn x-2=7 căn x-2-10
=>-5 căn x-2=-10
=>căn x-2=2
=>x-2=4
=>x=6
ĐKXĐ: $x - 2 ≥ 0 ⇔ x ≥ 2$
$2\sqrt{4(x - 2)} - \dfrac{2}{3} \sqrt{9(x - 2)} = \sqrt{49(x - 2)} - 10$
$⇔ 4 \sqrt{x - 2} - 2\sqrt{x - 2} = 7 \sqrt{x - 2} - 10$
$⇔ 5 \sqrt{x - 2} = 10$
$⇔ \sqrt{x - 2} = 2$
$⇔ x - 2 = 2^2$
$⇔ x = 6$




bài 2 câu 1,2,3,5,9





