Question

Giúp mình câu b với

Answer 1

a: \(A=\dfrac{\sqrt{x}-2+\sqrt{x}+2+x}{x-4}=\dfrac{x+2\sqrt{x}}{x-4}=\dfrac{\sqrt{x}}{\sqrt{x}-2}\)

b: \(A=\dfrac{2+\sqrt{3}}{2+\sqrt{3}-2}=\dfrac{2+\sqrt{3}}{\sqrt{3}}\)

\(\Leftrightarrow A-\dfrac{2}{\sqrt{3}}=\dfrac{\sqrt{3}}{\sqrt{3}}=1\)