\(B=\dfrac{\left(2-\sqrt{3}\right)\sqrt{4+2\sqrt{3}}}{\sqrt{4-2\sqrt{3}}}+\left(2+\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{3}+1}\right)\left(2-\dfrac{\sqrt{3}\left(\sqrt{3}-1\right)}{\sqrt{3}-1}\right)\)
\(=\dfrac{\left(2-\sqrt{3}\right)\sqrt{\left(\sqrt{3}+1\right)^2}}{\sqrt{\left(\sqrt{3}-1\right)^2}}+\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)\)
\(=\dfrac{\left(2-\sqrt{3}\right)\left(\sqrt{3}+1\right)}{\sqrt{3}-1}+4-3\)
\(=\dfrac{\left(2-\sqrt{3}\right)\left(\sqrt{3}+1\right)^2}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}+1\)
\(=\dfrac{\left(2-\sqrt{3}\right)\left(4+2\sqrt{3}\right)}{2}+1=\dfrac{2\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}{2}+1\)
\(=4-3+1=2\)
giúp mình ý a là đc ạ mình cảm ơn ạ
