\(230mA=\dfrac{230}{1000}=0,23A\)
\(250V=0,25kV\)
\(0,099A=0,099\cdot1000=99mA\)
\(3,2kV=3,2\cdot10^6=3200000mV\)
230mA = 0,23A 250V = 0,25kV
0,099A = 99 mA 3,2kV=3200000mV
a) 230 mA = 0,23A
b) 250 V = 0,25 kV
c) 0,099 A = 99 mA
d) 3,2 kV = 3200000 mV