ĐKXĐ: \(x\ge0\)
\(\Leftrightarrow3\sqrt{2x}+\dfrac{1}{7}.7\sqrt{2x}-6\sqrt{2x}+4=0\\ \Leftrightarrow3\sqrt{2x}+\sqrt{2x}-6\sqrt{2x}+4=0\\ \Leftrightarrow-2\sqrt{2x}=-4\\ \Leftrightarrow\sqrt{2x}=2\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\left(tm\right)\)