Question

Giup mik cay nha

Answer 1

Ta có: x-2y=6 => x=6+2y(*)

Theo bài ra ta có: x\(^2\)+3y+2=0(1)

Thay (*) vào (1) ta có: (6+2y)\(^2\)+ 3y+2=0

\(\Leftrightarrow\)36+24y+4y\(^2\)+3y+2=0

\(\Leftrightarrow\)4y\(^2\)+27y+38=0

\(\Leftrightarrow\)4y\(^2\)+8y+19y+38=0

\(\Leftrightarrow\)(4y+19)(y+2)=0

\(\Leftrightarrow\)\(\left[{}\begin{matrix}y=-2\\y=-4.75\end{matrix}\right.\)

+ khi y=-2 thì x=6-4=2 => 3a-3=0=> a=1

+khi y=-4.75 thì x=6-4.75\(\times\)2=-3.5=> 3a-3=-8.25=> a=-1.75

Vậy ............................

TICK CHO MIH NHA