Question

giúp mik câu 1,2,7,8,9,10 vs 

Answer 1

1)=\(\dfrac{2}{x}+\dfrac{3}{x-1}+\dfrac{1-4x}{x\left(x-1\right)}=\dfrac{2x-2+3x+1-4x}{x\left(x-1\right)}=\dfrac{x-1}{x\left(x-1\right)}\dfrac{1}{x}\)

2\(\dfrac{3}{x}+\dfrac{2}{x+2}+\dfrac{2-x}{x\left(x+2\right)}=\dfrac{3x+6+2x+2-x}{x\left(x-2\right)}=\dfrac{4x+8}{x\left(x+2\right)}=\dfrac{4\left(x+2\right)}{x\left(x+2\right)}=\dfrac{4}{x}\)

Answer 2

3)\(\dfrac{-3}{x}+\dfrac{x}{x+4}+\dfrac{-x^2}{2x\left(x+4\right)}=\dfrac{-3x-12+2x^2-x^2}{2x\left(x+4\right)}=\dfrac{-3x-12-x^2}{2x\left(x+4\right)}\)