\(a,P=\left(\dfrac{b-a}{\sqrt{b}-\sqrt{a}}-\dfrac{a\sqrt{a}-b\sqrt{b}}{a-b}\right):\dfrac{\left(\sqrt{b}-\sqrt{a}\right)^2+\sqrt{ab}}{\sqrt{a}+\sqrt{b}}\left(a\ne b;a,b\ge0\right)\)
\(P=\left(\dfrac{\left(\sqrt{b}-\sqrt{a}\right)\left(\sqrt{a}+\sqrt{b}\right)}{\sqrt{b}-\sqrt{a}}-\dfrac{\left(\sqrt{a}-\sqrt{b}\right)\left(a+\sqrt{ab}+b\right)}{\left(\sqrt{a}-\sqrt{b}\right)\left(\sqrt{a}+\sqrt{b}\right)}\right)\cdot\dfrac{\sqrt{a}+\sqrt{b}}{b-\sqrt{ab}+a}\)
\(P=\left(\left(\sqrt{a}+\sqrt{b}\right)-\dfrac{a+\sqrt{ab}+b}{\sqrt{a}+\sqrt{b}}\right)\cdot\dfrac{\sqrt{a}+\sqrt{b}}{a-\sqrt{ab}+b}\)
\(P=\dfrac{a+2\sqrt{ab}+b-a-\sqrt{ab}-b}{\sqrt{a}+\sqrt{b}}\cdot\dfrac{\sqrt{a}+\sqrt{b}}{a-\sqrt{ab}+b}\)
\(P=\dfrac{\sqrt{ab}}{a-\sqrt{ab}+b}\)
