Question

giúp iem với, tìm đkxđ vs ạ, thanks

Answer 1

a khác 0

Answer 2

a: \(P=\dfrac{\sqrt{a}+1}{\sqrt{a}\left(\sqrt{a}-1\right)}\cdot\dfrac{\left(\sqrt{a}-1\right)^2}{\sqrt{a}+1}=\dfrac{\sqrt{a}-1}{\sqrt{a}}\)

b: \(P-1=\dfrac{\sqrt{a}-1-\sqrt{a}}{\sqrt{a}}=\dfrac{-1}{\sqrt{a}}< 0\)