\(7.R1ntR2ntR3\Rightarrow\left\{{}\begin{matrix}a,\Rightarrow Uab=IA.\left(R1+R2+R3\right)=0,5\left(1+2+3\right)=3V\\b,\Rightarrow Uv=U23=Uab-U1=3-IA.R1=3-0,5=2,5V\\\end{matrix}\right.\)
\(8.\)\(R1ntR2ntR3\Rightarrow\left\{{}\begin{matrix}a,\Rightarrow Ia=\dfrac{Uv}{R2+R3}=\dfrac{15}{10+15}=0,6A\\b,Uab=Ia.\left(R1+R2+R3\right)=18V\\\end{matrix}\right.\)
\(9.\)\(R1ntR2\Rightarrow R1=\dfrac{Uab-Uv}{\dfrac{Uv}{R2}}=\dfrac{9-5}{\dfrac{5}{10}}=8\Omega\)
\(10.R1ntR2\)\(\Rightarrow Im=\dfrac{U}{R1+R2}=\dfrac{12}{3+7}=1,2A\)
\(11R1ntR2\Rightarrow Rtd=R1+R2=\dfrac{U}{Im}=\dfrac{12}{0,5}=24\left(\Omega\right)\Rightarrow R2=24-R1=20\Omega\)