Question

giuc minh voi nheuc

Answer 1

\(\left(4x-3\right)\left(\dfrac{3}{5}x+\dfrac{1}{2}\right)=0\)

\(=>4x-3=0\) hoặc \(\dfrac{3}{5}x+\dfrac{1}{2}=0\)

\(=>x=\dfrac{3}{4}\) hoặc x = -5/6

Answer 2

(4x - 3).(\(\dfrac{3}{5}\)x + \(\dfrac{1}{2}\)) = 0

=> TH1: 4x - 3 = 0

=> 4x =3

=> x = loại

=>TH2: (\(\dfrac{3}{5}\)x + \(\dfrac{1}{2}\)) = 0

=> \(\dfrac{3}{5}\) x = \(\dfrac{1}{2}\)

=> x = \(\dfrac{1}{2}\): \(\dfrac{3}{5}\)

=> x = \(\dfrac{5}{6}\)

Answer 3

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