\(4+\dfrac{x}{5}=\dfrac{5}{3}\\ \Rightarrow\dfrac{x}{5}=-\dfrac{7}{3}\\ \Rightarrow x=-\dfrac{35}{3}\)
\(4+\dfrac{x}{5}=\dfrac{5}{3}\)
=>\(\dfrac{x}{5}=\dfrac{5}{3}-4=-\dfrac{7}{3}\)
=>x=-7/3*5=-35/3
4+\(\dfrac{x}{5}\)=\(\dfrac{5}{3}\) \(\Leftrightarrow\)\(\dfrac{x}{5}\)=\(\dfrac{3}{5}\)-4 \(\Leftrightarrow\) \(\dfrac{x}{5}\)= \(\dfrac{-7}{3}\) \(\Rightarrow\)x=\(\dfrac{-35}{3}\)