\(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x^2-2x}\) ( ĐKXĐ : \(x\ne0;2\) )
\(\Leftrightarrow\dfrac{x\left(x+2\right)-\left(x-2\right)}{x\left(x-2\right)}=\dfrac{2}{x\left(x-2\right)}\)
=> \(x^2+2x-x+2=2\)
<=> \(\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
Mà \(x\ne0;2\Rightarrow x=-1\)
Vậy S = { -1 }