ĐKXĐ : \(m\ne1;m\ne-2\)
PT\(\Leftrightarrow m^2x-m^2+\left(m-2\right)x=1-2m\)
\(\Leftrightarrow x\left(m^2+m-2\right)-m^2+2m-1=0\)
\(\Leftrightarrow x\left(m-1\right)\left(m+2\right)=\left(m-1\right)^2\)
\(\Rightarrow x=\dfrac{\left(m-1\right)^2}{\left(m-1\right)\left(m+2\right)}=\dfrac{m-1}{m+2}\)
Vậy \(x=\dfrac{m-1}{m+2}\)