ĐKXĐ:\(x\ge\dfrac{3}{2}\)
Bình phương 2 vế, ta có:
\(2x+2\sqrt{\left(x-\sqrt{6x-9}\right)\left(x+\sqrt{6x-9}\right)}=6\)
\(\Leftrightarrow x+\sqrt{x^2-6x+9}=3\)
\(\Leftrightarrow x+\sqrt{\left(x-3\right)^2}=3\)
\(\Leftrightarrow2x-3=3\Leftrightarrow x=3\)(t/m)