\(sin3x-4sinx\cdot cos2x=0\\ \Leftrightarrow3sinx-4sin^3x-4sinx\left(1-2sin^2x\right)=0\Leftrightarrow4sin^3x-sinx=0\\ \Leftrightarrow\left[{}\begin{matrix}sinx=0\\2sin^2x=\frac{1}{2}\end{matrix}\right.\Leftrightarrow}\left[{}\begin{matrix}x=k\pi\\x=\pm\frac{\pi}{6}+n\pi\end{matrix}\right.\)