ĐKXĐ: \(x\ge-\frac{1}{3}\)
\(\Leftrightarrow\left(x+1\right)^2-2\left(x+1\right)\sqrt{3x+1}+3x+1+x+2-2\sqrt{\left(x+2\right)\left(2x+1\right)}+2x+1=0\)
\(\Leftrightarrow\left(x+1-\sqrt{3x+1}\right)^2+\left(\sqrt{x+2}-\sqrt{2x+1}\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=\sqrt{3x+1}\\\sqrt{x+2}=\sqrt{2x+1}\end{matrix}\right.\) \(\Rightarrow x=1\)