\(\dfrac{3x-1}{4}>2\)
\(\Leftrightarrow\dfrac{3x-1}{4}-2>0\)
\(\Leftrightarrow3x-1-8>0\)
\(\Leftrightarrow3x-9>0\)
\(\Leftrightarrow3x>9\)
\(\Leftrightarrow x>3\)
Vậy \(S=\left\{x|x>3\right\}\)
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