Bài 1: Tìm x biết: $\frac{\left(2009-x\right)^2+\left(2009-x\right..
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Giải các phương trình sau:
a) \(x^3-6x^2-9x+14=0\)
b) \(\frac{\left(2010-x\right)^2-\left(2010-x\right)\left(x-2011\right)+\left(x-2011\right)^2}{\left(2010-x\right)^2+\left(2010+x\right)\left(x-2011\right)+\left(x-2011\right)^2}\)
5 tháng 3 2021 lúc 21:27
Giải phương trình :a,\(\dfrac{2x 1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)b,\(\dfrac{3\left(2x 1\right)}{4}-5-\dfrac{3x 2}{10}=\dfrac{2\left(3x-1\right)}{5}\)\(c,\dfrac{x 1}{2009} \dfrac{x 3}{2007}=\dfrac{x 5}{2005} \dfrac{x 7}{2003}\)\(d,\dfrac{392-x...
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Các chế ơi, còn 10 câu nữa thui, sắp hết rùi.
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Giải các phương trình sau
16) 3left(x+5right)left(x+6right)left(x+7right)8x
17) left(x+6right)^4+left(x+4right)^482
18) left(x^2+6x+10right)^2+left(x+3right)left(3x^2+20x+36right)0
19) 2left(x^2+x+1right)^2-7left(x-1right)^213left(x^3-1right)
20) left(x+2008right)^4+left(x+2009right)^4dfrac{1}{8}
21) x^4+18x13x^2+5
22) dfrac{1}{5x^2}+dfrac{1}{x^2-9x+36}dfrac{1}{x^2-4x+16}
23) dfrac{left(x+1right)^2...
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Các chế ơi, còn 10 câu nữa thui, sắp hết rùi.
FIGHTING!
JIAYOU!
HWAITING!
GAMBATTEYO!
Giải các phương trình sau
16) \(3\left(x+5\right)\left(x+6\right)\left(x+7\right)=8x\)
17) \(\left(x+6\right)^4+\left(x+4\right)^4=82\)
18) \(\left(x^2+6x+10\right)^2+\left(x+3\right)\left(3x^2+20x+36\right)=0\)
19) \(2\left(x^2+x+1\right)^2-7\left(x-1\right)^2=13\left(x^3-1\right)\)
20) \(\left(x+2008\right)^4+\left(x+2009\right)^4=\dfrac{1}{8}\)
21) \(x^4+18x=13x^2+5\)
22) \(\dfrac{1}{5x^2}+\dfrac{1}{x^2-9x+36}=\dfrac{1}{x^2-4x+16}\)
23) \(\dfrac{\left(x+1\right)^2}{x^2+2x+2}-\dfrac{x^2+2x}{\left(x+1\right)^2}=\dfrac{1}{90}\)
24) \(\left(2x^2+x-2013\right)^2+4\left(x^2-5x-2012\right)^2=4\left(2x^2+x-2013\right)\left(x^2-5x-2012\right)\)
25)\(\dfrac{x-4}{x+1}+\dfrac{x-4}{x+1}+\dfrac{8}{3}=\dfrac{x-8}{x+2}+\dfrac{x+8}{x-2}\)
Thanks các cậu vì đã giúp mk
cho M= \(\dfrac{x^2}{\left(x+y\right)\left(1-y\right)}\)-\(\dfrac{y^2}{\left(x+y\right)\left(1+x\right)}\)-\(\dfrac{X^2y^2}{\left(1+x\right)\left(1-y\right)}\)
a, rút gọn M
b, tìm các cặp số nguyên x,y để biểu thức có giá trị là -2010
\(\dfrac{\left(x+1\right)\left(x+2\right)-\left[\left(x+1\right)-x\right]}{\left(x+2\right)\left[\left(x+1\right)^2-x\right]}-\dfrac{\left(x+1\right)+2-\left(x+1\right)\left[\left(x+1\right)^3+1\right]}{\left(x+1\right)^3+1}\)
a) \(8\left(x+\dfrac{1}{x}\right)^2+4\left(x^2+\dfrac{1}{x^2}\right)^2-4\left(x^2+\dfrac{1}{x^2}\right)\left(x+\dfrac{1}{x}\right)^2=\left(x+4\right)^2\)
b) \(\left(6x+7\right)^2\left(3x+4\right)\left(x+1\right)=6\)
c) \(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)=840\)
Giải phương trình:
\(\left(\dfrac{7x-x^2}{x+1}\right)\left(\dfrac{7+x^2}{x+1}\right)=10\)
Giải phương trình:
a, \(\left(x+1+\dfrac{1}{x}\right)^2=\left(x-1-\dfrac{1}{x}\right)^2\)
b, \(\left(x-1\right)^2+3x^2=0\)
1) giải phương trình :
a) left(2+3right)left(dfrac{3x+8}{2-7x}+1right)left(x-5right)left(dfrac{3x+8}{2-7x}+1right)
b) dfrac{7x+10}{x+1}left(x^2-x-2right)-dfrac{7x+10}{x+1}left(2x^2-3x-5right)0
c) dfrac{2x+5}{x+3}+1dfrac{4}{x^2+2x-3}-dfrac{3x-1}{1-x}
d) dfrac{13}{2x^2+x-21}+dfrac{1}{2x+7}+dfrac{6}{9-x^2}0
i) dfrac{x-49}{50}+dfrac{x-50}{49}dfrac{49}{x-50}+dfrac{50}{x-49}
k) dfrac{1+dfrac{x}{x+3}}{1-dfrac{x}{x+3}}3
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1) giải phương trình :
a) \(\left(2+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
b) \(\dfrac{7x+10}{x+1}\left(x^2-x-2\right)-\dfrac{7x+10}{x+1}\left(2x^2-3x-5\right)=0\)
c) \(\dfrac{2x+5}{x+3}+1=\dfrac{4}{x^2+2x-3}-\dfrac{3x-1}{1-x}\)
d) \(\dfrac{13}{2x^2+x-21}+\dfrac{1}{2x+7}+\dfrac{6}{9-x^2}=0\)
i) \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)
k) \(\dfrac{1+\dfrac{x}{x+3}}{1-\dfrac{x}{x+3}}=3\)