Question

Giải phương trình

\(\dfrac{4+x}{3}-\dfrac{x-\dfrac{x-1}{2}}{2}+\dfrac{x-3}{4}=\dfrac{6-2x}{2}\)

Answer 1

\(\dfrac{4+x}{3}-\dfrac{x-\dfrac{x-1}{2}}{2}+\dfrac{x-3}{4}=\dfrac{6-2x}{2}\)

\(\Leftrightarrow\dfrac{4+x}{3}-\dfrac{\dfrac{2x-x+1}{2}}{2}+\dfrac{x-3}{4}=\dfrac{6-2x}{2}\)

\(\Leftrightarrow\dfrac{4+x}{3}-\dfrac{\dfrac{x+1}{2}}{2}+\dfrac{x-3}{4}=\dfrac{6-2x}{2}\)

\(\Leftrightarrow\dfrac{4+x}{3}-\dfrac{x+1}{4}+\dfrac{x-3}{4}=\dfrac{6-2x}{2}\)

\(\Leftrightarrow\dfrac{4+x}{3}-1=\dfrac{6-2x}{2}\)

\(\Leftrightarrow8+2x-6-18+6x=0\)

\(\Leftrightarrow8x-16=0\)

\(\Leftrightarrow x=2\)