\(4x^3-16x=0\)
\(\Leftrightarrow4x\cdot\left(x^2-4\right)=0\)
\(\Leftrightarrow4x\cdot\left(x-2\right)\cdot\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=0\\x-2=0\\x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
\(\Leftrightarrow\)\(4x(x^{2}-4)=0\)
\(\Leftrightarrow\)\(\left[\begin{array}{} 4x=0\\ x^{2}-4=0 \end{array} \right.\)
\(\Leftrightarrow\)\(\left[\begin{array}{} x=0\\ x=2,x=-2 \end{array} \right.\)
Ta có: \(4x^3-16x=0\)
\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
