\(2m^2-1=0\)
\(\Leftrightarrow m^2=\frac{1}{2}\)
\(\Leftrightarrow m=+\sqrt{\frac{1}{2}}\)
\(2m^2-9=0\)
\(\Leftrightarrow m^2=\frac{9}{2}\)
\(m=\pm\sqrt{\frac{9}{2}}\)
Vậy ....
a) \(2m^2-1=0\)
\(\Leftrightarrow2m^2=1\)
\(\Leftrightarrow m^2=\frac{1}{2}\)
\(\Leftrightarrow m=\sqrt{\frac{1}{2}}\)
b) \(2m^2-9=0\)
\(\Leftrightarrow2m^2=9\)
\(\Leftrightarrow m^2=\frac{9}{2}\)
\(\Leftrightarrow m=\sqrt{\frac{9}{2}}\)
bổ sung nha
Do m là mũ 2
a) \(m=\pm\sqrt{\frac{1}{2}}\)
b) \(m=\pm\sqrt{\frac{9}{2}}\)